127 lines
4 KiB
C
127 lines
4 KiB
C
/* Copyright (C) 2008-2022 Free Software Foundation, Inc.
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Contributor: Joern Rennecke <joern.rennecke@embecosm.com>
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on behalf of Synopsys Inc.
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This file is part of GCC.
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GCC is free software; you can redistribute it and/or modify it under
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the terms of the GNU General Public License as published by the Free
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Software Foundation; either version 3, or (at your option) any later
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version.
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GCC is distributed in the hope that it will be useful, but WITHOUT ANY
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WARRANTY; without even the implied warranty of MERCHANTABILITY or
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FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
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for more details.
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Under Section 7 of GPL version 3, you are granted additional
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permissions described in the GCC Runtime Library Exception, version
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3.1, as published by the Free Software Foundation.
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You should have received a copy of the GNU General Public License and
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a copy of the GCC Runtime Library Exception along with this program;
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see the files COPYING3 and COPYING.RUNTIME respectively. If not, see
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<http://www.gnu.org/licenses/>. */
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/* We use a polynom similar to a Tchebycheff polynom to get an initial
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seed, and then use a newton-raphson iteration step to get an
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approximate result
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If this result can't be rounded to the exact result with confidence, we
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round to the value between the two closest representable values, and
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test if the correctly rounded value is above or below this value.
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Because of the Newton-raphson iteration step, an error in the seed at X
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is amplified by X. Therefore, we don't want a Tchebycheff polynom
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or a polynom that is close to optimal according to the maximum norm
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on the errro of the seed value; we want one that is close to optimal
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according to the maximum norm on the error of the result, i.e. we
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want the maxima of the polynom to increase linearily.
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Given an interval [X0,X2) over which to approximate,
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with X1 := (X0+X2)/2, D := X1-X0, F := 1/D, and S := D/X1 we have,
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like for Tchebycheff polynoms:
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P(0) := 1
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but then we have:
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P(1) := X + S*D
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P(2) := 2 * X^2 + S*D * X - D^2
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Then again:
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P(n+1) := 2 * X * P(n) - D^2 * P (n-1)
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*/
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int
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main (void)
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{
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long double T[5]; /* Taylor polynom */
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long double P[5][5];
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int i, j;
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long double X0, X1, X2, S;
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long double inc = 1./64;
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long double D = inc*0.5;
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long i0, i1, i2;
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memset (P, 0, sizeof (P));
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P[0][0] = 1.;
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for (i = 1; i < 5; i++)
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P[i][i] = 1 << i-1;
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P[2][0] = -D*D;
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for (X0 = 1.; X0 < 2.; X0 += inc)
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{
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X1 = X0 + inc * 0.5;
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X2 = X1 + inc;
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S = D / X1;
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T[0] = 1./X1;
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for (i = 1; i < 5; i++)
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T[i] = T[i-1] * -T[0];
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#if 0
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printf ("T %1.8f %f %f %f %f\n", (double)T[0], (double)T[1], (double)T[2],
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(double)T[3], (double)T[4]);
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#endif
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P[1][0] = S*D;
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P[2][1] = S*D;
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for (i = 3; i < 5; i++)
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{
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P[i][0] = -D*D*P[i-2][0];
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for (j = 1; j < i; j++)
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P[i][j] = 2*P[i-1][j-1]-D*D*P[i-2][j];
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}
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#if 0
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printf ("P3 %1.8f %f %f %f %f\n", (double)P[3][0], (double)P[3][1], (double)P[3][2],
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(double)P[3][3], (double)P[3][4]);
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printf ("P4 %1.8f %f %f %f %f\n", (double)P[4][0], (double)P[4][1], (double)P[4][2],
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(double)P[4][3], (double)P[4][4]);
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#endif
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for (i = 4; i > 1; i--)
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{
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long double a = T[i]/P[i][i];
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for (j = 0; j < i; j++)
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T[j] -= a * P[i][j];
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}
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#if 0
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printf ("A %1.8f %f %f\n", (double)T[0], (double)T[1], (double)T[2]);
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#endif
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#if 0
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i2 = T[2]*512;
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long double a = (T[2]-i/512.)/P[2][2];
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for (j = 0; j < 2; j++)
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T[j] -= a * P[2][j];
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#else
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i2 = 0;
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#endif
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for (i = 0, i0 = 0; i < 4; i++)
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{
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long double T0, Ti1;
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i1 = T[1]*8192. + i0 / (long double)(1 << 19) - 0.5;
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i1 = - (-i1 & 0x1fff);
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Ti1 = ((unsigned)(-i1 << 19) | i0) /-(long double)(1LL<<32LL);
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T0 = T[0] - (T[1]-Ti1)/P[1][1] * P[1][0] - (X1 - 1) * Ti1;
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i0 = T0 * 512 * 1024 + 0.5;
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i0 &= 0x7ffff;
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}
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#if 0
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printf ("A %1.8f %f %f\n", (double)T[0], (double)T[1], (double)T[2]);
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#endif
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printf ("\t.long 0x%x\n", (-i1 << 19) | i0);
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}
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return 0;
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}
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