remove overfull hbox
This commit is contained in:
parent
ba585b51ca
commit
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8 changed files with 43 additions and 46 deletions
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@ -7,7 +7,7 @@
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\begin{figure}[h!]
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\begin{figure}[h!]
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\centering
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\centering
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\begin{subfigure}{.5\textwidth}
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\begin{subfigure}{.6\textwidth}
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\begin{tikzpicture}
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\begin{tikzpicture}
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\sbEntree{A}
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\sbEntree{A}
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\sbBlocL{E}{Échantilloneur}{A}
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\sbBlocL{E}{Échantilloneur}{A}
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@ -24,8 +24,8 @@
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à temps\\ continu
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à temps\\ continu
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\end{tabular}};
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\end{tabular}};
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\end{tikzpicture}
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\end{tikzpicture}
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\end{subfigure}~~%
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\end{subfigure}%
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\begin{subfigure}{.5\textwidth}
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\begin{subfigure}{.4\textwidth}
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\begin{tikzpicture}
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\begin{tikzpicture}
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\begin{axis}
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\begin{axis}
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[axis lines = middle, width=8cm,
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[axis lines = middle, width=8cm,
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@ -40,7 +40,6 @@
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\end{axis}
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\end{axis}
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\end{tikzpicture}
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\end{tikzpicture}
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\end{subfigure}
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\end{subfigure}
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\end{figure}
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\end{figure}
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On prélève la valeur de $x_c(t)$ à un instant de l'ensemble discret $nT_e, n\in\N$.
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On prélève la valeur de $x_c(t)$ à un instant de l'ensemble discret $nT_e, n\in\N$.
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@ -343,7 +343,7 @@ Pour caractériser les fenêtres, on utilise les paramètres suivants :
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\begin{center}
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\begin{center}
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\renewcommand{\arraystretch}{1.5}
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\renewcommand{\arraystretch}{1.5}
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\begin{tabular}{|c|c|c|c|c|c|}
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\begin{tabular}{|c|c|c|c|c|p{4cm}|}
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\hline
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\hline
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& Rect & Tria & Hamming & Hanning & B-H \\
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& Rect & Tria & Hamming & Hanning & B-H \\
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\hline
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\hline
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@ -19,13 +19,11 @@ Filtre \\linéaire
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\end{tikzpicture}
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\end{tikzpicture}
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\caption{Traitement numérique d'un signal analogique}
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\caption{Traitement numérique d'un signal analogique}
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\end{figure}
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\end{figure}
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\section{Convertisseur numérique analogique}
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\section{Convertisseur numérique analogique}
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\subsection{Principes}
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\subsection{Principes}
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% CNA
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% CNA
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\begin{center}
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\begin{figure}[H]
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\centering
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\begin{tikzpicture}
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\begin{tikzpicture}
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\draw (0,0) node[left]{$\underbracket{a_{n-1}...a_0}_{\text{n bits}}$} -- (1,0) (1,1)node[below right]{$\#$} rectangle (3,-1)node[above left]{$\sim$} (1,-1) -- (3,1);
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\draw (0,0) node[left]{$\underbracket{a_{n-1}...a_0}_{\text{n bits}}$} -- (1,0) (1,1)node[below right]{$\#$} rectangle (3,-1)node[above left]{$\sim$} (1,-1) -- (3,1);
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\draw[-latex] (3,0) -- ++(1,0) node[right]{$x$};
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\draw[-latex] (3,0) -- ++(1,0) node[right]{$x$};
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@ -33,10 +31,9 @@ Filtre \\linéaire
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\[
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\[
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x =V_{ref} \sum_{k=0}^{n-1}a_k2^k
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x =V_{ref} \sum_{k=0}^{n-1}a_k2^k
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\]
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\]
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\end{center}
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\caption{principe du CNA}
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\end{figure}
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\subsection{Caractéristiques de transfert}
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\subsection{Caractéristiques de transfert}
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\begin{figure}[H]
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\begin{figure}[H]
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\centering
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\centering
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\begin{tikzpicture}
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\begin{tikzpicture}
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@ -157,7 +154,7 @@ On a les mêmes problèmes possibles sur les CAN, induits par des problèmes de
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%\img{0.5}{4/13}
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%\img{0.5}{4/13}
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\begin{figure}[H]
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\begin{figure}[H]
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\begin{center}
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\begin{center}
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\begin{subfigure}{0.5\linewidth}
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\begin{subfigure}{0.45\linewidth}
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\centering
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\centering
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\begin{tikzpicture}
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\begin{tikzpicture}
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\foreach \y/\l in {-3/0,-2/1,0/k,1/n-2,2/n-1}
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\foreach \y/\l in {-3/0,-2/1,0/k,1/n-2,2/n-1}
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@ -170,7 +167,7 @@ On a les mêmes problèmes possibles sur les CAN, induits par des problèmes de
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\end{tikzpicture}
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\end{tikzpicture}
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\subcaption{Schéma théorique}
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\subcaption{Schéma théorique}
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\end{subfigure}%
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\end{subfigure}%
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\begin{subfigure}{0.5\linewidth}
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\begin{subfigure}{0.55\linewidth}
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\begin{tikzpicture}
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\begin{tikzpicture}
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\foreach \y/\l in {-3/0,-2/1,0/k,1/n-2,2/n-1}
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\foreach \y/\l in {-3/0,-2/1,0/k,1/n-2,2/n-1}
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{\draw (0,\y)to[spst,l=$a_{\l}$] ++(1,0) to[R,l={$2^{\l}I_0$}]++(3,0);}
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{\draw (0,\y)to[spst,l=$a_{\l}$] ++(1,0) to[R,l={$2^{\l}I_0$}]++(3,0);}
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@ -20,11 +20,12 @@ Transmettre le max de donnée avec un fiabilité maximale
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\begin{figure}[H]
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\begin{figure}[H]
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\centering
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\centering
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\begin{tikzpicture}
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\begin{tikzpicture}
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[every node/.style={draw,rectangle,minimum height=4em,node distance=0.5cm,scale=0.8}]
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[every node/.style={draw,rectangle,minimum height=4em,node
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distance=0.5cm,scale=0.8,inner sep=2pt}]
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\node (S) at (0,0){Source};
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\node (S) at (0,0){Source};
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\node (CS) [right= of S]{\begin{tabular}{c}Codage \\ source\end{tabular}};
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\node (CS) [right= of S]{\begin{tabular}{c}Codage \\ source\end{tabular}};
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\node (CC) [right= of CS]{\begin{tabular}{c}Codage \\ canal\end{tabular}};
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\node (CC) [right= of CS]{\begin{tabular}{c}Codage \\ canal\end{tabular}};
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\node (CBB) [right= of CC]{\begin{tabular}{c}Codage B de B \\ modulation\end{tabular}};
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\node (CBB) [right= of CC]{\begin{tabular}{c}Codage B de B\\ modulation\end{tabular}};
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\node (C) [right= of CBB]{Canal};
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\node (C) [right= of CBB]{Canal};
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\node (A) [right= of C][adder]{};
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\node (A) [right= of C][adder]{};
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\node (Demod)[right= of A]{Demod};
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\node (Demod)[right= of A]{Demod};
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@ -125,7 +126,7 @@ Où $A(t)$ et $\Phi(t)$ sont les amplitudes et phases instantanée.
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\node[below left] at (-2,0) {11};
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\node[below left] at (-2,0) {11};
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\node[below right] at (0,-2) {10};
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\node[below right] at (0,-2) {10};
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\end{scope}
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\end{scope}
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\begin{scope}[shift={(4,-3)}]
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\begin{scope}[shift={(3.5,-2.2)}]
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\begin{axis}
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\begin{axis}
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[axis lines = middle,height=6cm, width=12cm,
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[axis lines = middle,height=6cm, width=12cm,
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xmin=0,xmax=360,ymin=-1,ymax=1,
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xmin=0,xmax=360,ymin=-1,ymax=1,
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@ -147,7 +147,7 @@ Soit $IES = 0 $
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La DSP rectangulaire centrée en fait partie.
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La DSP rectangulaire centrée en fait partie.
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\begin{rem}
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\begin{rem}
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On a cepedant des lobs secondaire elevé dans la DSP (sinus
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On a cepedant des lobs secondaire élevé dans la DSP (sinus
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cardinal pur), ce qui peux être dramatique en cas de mauvaise
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cardinal pur), ce qui peux être dramatique en cas de mauvaise
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synchronisation. On cherche donc d'autre fonctions candidates avec
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synchronisation. On cherche donc d'autre fonctions candidates avec
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des lobes secondaires moins élevé.
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des lobes secondaires moins élevé.
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@ -159,7 +159,7 @@ Soit $IES = 0 $
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\[G(f) =
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\[G(f) =
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\begin{cases}
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\begin{cases}
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T & \forall f \in \left[-\frac{1-\alpha}{2T},\frac{1-\alpha}{2T}\right]\\
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T & \forall f \in \left[-\frac{1-\alpha}{2T},\frac{1-\alpha}{2T}\right]\\
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\frac{T}{2}\left[1+\sin\left(\frac{\pi t}{\alpha}\left(\frac{1}{2T}-|f|\right)\right)\right] & \frac{1-\alpha}{2T}\le |f| \le \frac{1+\alpha}{2T}\\
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\frac{T}{2}\left[1+\sin\left(\frac{\pi T}{\alpha}\left(\frac{1}{2T}-|f|\right)\right)\right] & \frac{1-\alpha}{2T}\le |f| \le \frac{1+\alpha}{2T}\\
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0 & \text{ sinon}
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0 & \text{ sinon}
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\end{cases}
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\end{cases}
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\]
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\]
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@ -181,14 +181,14 @@ Soit $IES = 0 $
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\begin{figure}[H]
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\begin{figure}[H]
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\centering
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\centering
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\begin{subfigure}{0.5\textwidth}
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\begin{subfigure}{0.5\textwidth}
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\centering
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\caption{Réponse fréquentielle}
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\caption{Réponse fréquentielle}
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\label{fig:label}
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\end{subfigure}%
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\end{subfigure}%
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\begin{subfigure}{0.5\textwidth}
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\begin{subfigure}{0.5\textwidth}
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\centering
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\centering
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\caption{réponse temporelle}
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\caption{réponse temporelle}
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\label{fig:label}
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\end{subfigure}
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\end{subfigure}
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\caption{Différents filtres respectant le critère de Nyquist}
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\caption{Différents filtres respectant le critère de Nyquist}
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\end{figure}
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\end{figure}
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@ -220,9 +220,3 @@ Soit $IES = 0 $
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la capacité de Shannon.
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la capacité de Shannon.
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\end{prop}
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\end{prop}
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\end{document}
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "main"
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%%% End:
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@ -11,10 +11,9 @@ On rappele le schéma de chaine de transimission numérique:
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\centering
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\centering
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\begin{tikzpicture}
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\begin{tikzpicture}
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[every node/.style={draw,rectangle,minimum height=4em,node distance=0.5cm,scale=0.8}]
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[every node/.style={draw,rectangle,minimum height=4em,node distance=0.5cm,scale=0.8}]
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\node (S) at (0,0){Source};
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\node (CS){\begin{tabular}{c}Codage \\ source\end{tabular}};
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\node (CS) [right= of S]{\begin{tabular}{c}Codage \\ source\end{tabular}};
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\node (CC) [right= of CS]{\begin{tabular}{c}Codage \\ canal\end{tabular}};
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\node (CC) [right= of CS]{\begin{tabular}{c}Codage \\ canal\end{tabular}};
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\node (CBB) [right= of CC]{\begin{tabular}{c}Filtre emission \\ $G(f)$\end{tabular}};
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\node (CBB) [right= of CC]{\begin{tabular}{c}Emission \\ $G(f)$\end{tabular}};
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\node (C) [right= of CBB]{
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\node (C) [right= of CBB]{
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\begin{tabular}{c}
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\begin{tabular}{c}
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Canal\\ H(f)
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Canal\\ H(f)
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@ -22,8 +21,7 @@ Canal\\ H(f)
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};
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};
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\node (A) [right= of C][adder]{};
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\node (A) [right= of C][adder]{};
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\node (Demod)[right= of A]{
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\node (Demod)[right= of A]{
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\begin{tabular}{c}
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\begin{tabular}{c}Reception\\ Gr(f)
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filtre de Reception\\ Gr(f)
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\end{tabular}
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\end{tabular}
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};
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};
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\node (E) [right= of Demod]{
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\node (E) [right= of Demod]{
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@ -7,7 +7,10 @@
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\module{UE433}
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\module{UE433}
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\usetikzlibrary{trees}
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\usetikzlibrary{trees}
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\renewcommand{\thechapter}{\thepart-\arabic{chapter}}
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\makeatletter
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\@addtoreset{chapter}{part}
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\makeatother
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\begin{document}
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\begin{document}
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\maketitle
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\maketitle
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\tableofcontents
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\tableofcontents
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Codage\\ +\\ modulation
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Codage\\ +\\ modulation
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\end{tabular}
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\end{tabular}
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}{CAN}
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}{CAN}
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\sbBlocL{trans}{
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\sbBlocL{trans}{Canal}{num}
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\begin{tabular}{c}
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Canal \\de\\ propagation
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\end{tabular}}{num}
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\sbBlocL{demod}{
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\sbBlocL{demod}{
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\begin{tabular}{c}
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\begin{tabular}{c}
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Décodage \\+\\ Démodulation
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Décodage \\+\\ Démodulation
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24
cours.cls
24
cours.cls
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\LoadClass[12pt,a4paper,french,titlepage]{book}
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\LoadClass[12pt,a4paper,french,titlepage]{book}
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\RequirePackage[french]{babel} % pour ecrire en francais
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\RequirePackage[french]{babel} % pour ecrire en francais
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\RequirePackage[left=2.00cm, right=2.00cm, top=3.00cm, bottom=3.00cm]{geometry} % la mise en page
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\RequirePackage[left=2.00cm, right=2.00cm, top=3.00cm, bottom=3.00cm,headheight=15pt]{geometry} % la mise en page
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% Packages
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% Packages
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\RequirePackage[utf8]{inputenc} % encodage
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\RequirePackage[utf8]{inputenc} % encodage
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\fancyhf {}
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\fancyhf {}
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\renewcommand{\chaptermark}[1]{\markboth{\bsc{\@chapapp~\thechapter{} :} #1}{}}
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\renewcommand{\chaptermark}[1]{\markboth{\bsc{\@chapapp~\thechapter{}~:} #1}{}}
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\renewcommand{\sectionmark}[1]{\markright{\thesection.{} #1}}
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\renewcommand{\sectionmark}[1]{\markright{\thesection.{} #1}}
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\renewcommand{\headrulewidth}{1pt} %Epaisseur de la ligne.
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\renewcommand{\headrulewidth}{1pt} %Epaisseur de la ligne.
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\RequirePackage{needspace}
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\RequirePackage{needspace}
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\renewcommand{\section}{
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% \renewcommand{\section}{
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\needspace{0.3\textheight}%
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% \needspace{0.2\textheight}%
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\@startsection {section}{1}{\z@}%
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% \@startsection {section}{1}{\z@}%
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{-3.5ex \@plus -1ex \@minus -.2ex}%
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% {-3.5ex \@plus -1ex \@minus -.2ex}%
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{2.3ex \@plus.2ex}%
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% {2.3ex \@plus.2ex}%
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{\reset@font\Large\bfseries}}
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% {\reset@font\Large\bfseries}
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% }
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\raggedbottom
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\raggedbottom
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\setcounter{secnumdepth}{3}
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\setcounter{secnumdepth}{3}
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\renewcommand{\thesection}{\arabic{section}}
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\renewcommand{\thesection}{\arabic{section}}
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\RequirePackage{titletoc}
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\titlecontents*{chapter}% <section-type>
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[0pt]% <left>
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{}% <above-code>
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{\bfseries \thecontentslabel\quad}% <numbered-entry-format>
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{}% <numberless-entry-format>
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{\bfseries\hfill\contentspage}% <filler-page-format>
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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