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bsd: Fix set_key() sequence number endian issue

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In set_key handler, the seq[8] is in little endian order defined by
WPA. BSD kernel uses a u_int64_t value ik_keyrsc to represent it
internally. The kernel expects the native endian order for the value.
Thus, we need to detect the endian order and swap bytes when
necessary.
This commit is contained in:
Zhu Yi 2011-06-23 15:47:21 +03:00 committed by Jouni Malinen
parent 29fbc52251
commit c3b0a1c8ad
1 changed files with 13 additions and 1 deletions
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14
src/drivers/driver_bsd.c
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@ -345,8 +345,20 @@ bsd_set_key(const char *ifname, void *priv, enum wpa_alg alg,
if (wk.ik_keyix != IEEE80211_KEYIX_NONE && set_tx)
wk.ik_flags |= IEEE80211_KEY_DEFAULT;
wk.ik_keylen = key_len;
if (seq)
if (seq) {
#ifdef WORDS_BIGENDIAN
/*
* wk.ik_keyrsc is in host byte order (big endian), need to
* swap it to match with the byte order used in WPA.
*/
int i;
u8 *keyrsc = (u8 *) &wk.ik_keyrsc;
for (i = 0; i < seq_len; i++)
keyrsc[WPA_KEY_RSC_LEN - i - 1] = seq[i];
#else /* WORDS_BIGENDIAN */
os_memcpy(&wk.ik_keyrsc, seq, seq_len);
#endif /* WORDS_BIGENDIAN */
}
os_memcpy(wk.ik_keydata, key, key_len);
return set80211var(priv, IEEE80211_IOC_WPAKEY, &wk, sizeof(wk));