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Use throughput estimate-based BSS selection with larger SNR difference

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Previously, the est_throughput comparison was done only when SNR
difference was less than 5 dB. Since the throughput estimation take into
account SNR, this can be done in more cases. For now, add a conservative
2 dB more to the difference so that any SNR difference below 7 dB
results in BSS selection based on throughput estimates.

In addition, the throughput estimates require SNR values to be
available, so separate this from the 5 GHz preference that can be done
based on either SNR or qual values.

Signed-off-by: Jouni Malinen <j@w1.fi>
This commit is contained in:
Jouni Malinen 2017-02-16 11:09:04 +02:00
parent 1420414878
commit b4d56efb1a
1 changed files with 4 additions and 2 deletions
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6
wpa_supplicant/scan.c
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@ -1841,10 +1841,12 @@ static int wpa_scan_result_compar(const void *a, const void *b)
}
/* if SNR is close, decide by max rate or frequency band */
if ((snr_a && snr_b && abs(snr_b - snr_a) < 5) ||
(wa->qual && wb->qual && abs(wb->qual - wa->qual) < 10)) {
if (snr_a && snr_b && abs(snr_b - snr_a) < 7) {
if (wa->est_throughput != wb->est_throughput)
return wb->est_throughput - wa->est_throughput;
}
if ((snr_a && snr_b && abs(snr_b - snr_a) < 5) ||
(wa->qual && wb->qual && abs(wb->qual - wa->qual) < 10)) {
if (IS_5GHZ(wa->freq) ^ IS_5GHZ(wb->freq))
return IS_5GHZ(wa->freq) ? -1 : 1;
}