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DFS: Consider non-contiguous channels

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When looking for a new operating channel, consider the case of
non-contiguous channels when checking all the needed channels (e.g., the
driver might support channels 36, 38, 40, so look for channels 36+40
explicitly, instead of failing when encountering channel 38).

Signed-off-by: Eliad Peller <eliad@wizery.com>
This commit is contained in:
Eliad Peller 2015-03-19 16:41:41 +02:00 committed by Jouni Malinen
parent 6ceea4c3cb
commit 56ef99255c
1 changed files with 17 additions and 3 deletions
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20
src/ap/dfs.c
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@ -122,6 +122,20 @@ static int dfs_is_chan_allowed(struct hostapd_channel_data *chan, int n_chans)
}
static struct hostapd_channel_data *
dfs_get_chan_data(struct hostapd_hw_modes *mode, int freq, int first_chan_idx)
{
int i;
for (i = first_chan_idx; i < mode->num_channels; i++) {
if (mode->channels[i].freq == freq)
return &mode->channels[i];
}
return NULL;
}
static int dfs_chan_range_available(struct hostapd_hw_modes *mode,
int first_chan_idx, int num_chans,
int skip_radar)
@ -135,9 +149,9 @@ static int dfs_chan_range_available(struct hostapd_hw_modes *mode,
first_chan = &mode->channels[first_chan_idx];
for (i = 0; i < num_chans; i++) {
chan = &mode->channels[first_chan_idx + i];
if (first_chan->freq + i * 20 != chan->freq)
chan = dfs_get_chan_data(mode, first_chan->freq + i * 20,
first_chan_idx);
if (!chan)
return 0;
if (!dfs_channel_available(chan, skip_radar))