heptagon/test/good/array1.ept
Cédric Pasteur 2fdf2855d3 Added a new truncated select operator
a[>e<] returns the element in the array at index
e, a[0] if e < 0 and a[n-1] if e >= n
2011-03-22 22:12:59 +01:00

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const n:int = 10
const m:int = 10
node concatenate(a:int^n; b:int^m) returns (o1, o2: int^(n+m))
let
o1 = a @ b;
o2 = b @ a;
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node slicing (a:int^n) returns (u1,u2 : int^3)
let
u1 = a[0 .. 2];
u2 = a[3 .. 5];
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node elt (a:int^m) returns (o:int^m)
var x : int;
let
x = a[2] + 1;
o = [ a with [1] = x ];
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node upd_dyn(a:int^m; i:int) returns (o:int^m)
let
o = [ a with [i] = a[0] ];
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node elt_dyn (a:int^m; i:int) returns (o:int^m)
var x : int;
let
x = a.[i] default 3;
o = [ a with [1] = x ];
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node ten (i: int) returns (o:int^m)
let
o = i^m;
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node constant(a,b:int) returns (o:int^4)
let
o = [a,b,a,b];
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node test1() returns (r1,r2: int^3)
var x,y : int^10; z,t : int^20;
let
x = ten(3);
y = ten(4);
(z,t) = concatenate(x,y);
(r1,r2) = slicing(x);
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node elt_trunc (a:int^m^m; i,j:int) returns (o : int)
let
o = a[>i<][>j<];
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